Harmonic phonon energy

$\displaystyle E = \sum_{\mathbf{k},\nu}\hbar\omega(\mathbf{k},\nu)\Bigl[\frac{1}{2} + \frac{1}{\exp(\hbar\omega(\mathbf{k},\nu)/k_B T)-1}\Bigr]$ (3.12)



togo 2009-02-12
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