Helmholtz free energy

\begin{displaymath}\begin{split}F &= -k_B T \ln Z \\ &= \varphi + \frac{1}{2} \s...
...[1 -\exp(-\hbar\omega(\mathbf{k},\nu)/k_B T) \bigr] \end{split}\end{displaymath} (3.15)



togo 2009-02-12
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